难度Easy
原题连接
内容描述
Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Example 1:
Input: haystack = "hello", needle = "ll"
Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba"
Output: -1
Clarification:
What should we return when needle is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().
思路 - 时间复杂度: O(N)- 空间复杂度: O(1)******
这题直接遍历 haystack ,匹配到与 needle 第一个字符相等时,就遍历 needle,挨个比较字符。
class Solution {
public:
int strStr(string haystack, string needle) {
int j = 0,i = 0,index= 0;
while(i < haystack.size() && j < needle.size())
{
if(haystack[i] == needle[j])
{
if(!j)
index = i;
j++;
i++;
}
else
{
i = ++index;
j = 0;
}
}
if(j == needle.size())
return index;
return -1;
}
};