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Translational symmetry in RBM #1266

Answered by PhilipVinc
abukva asked this question in Q&A
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Hi @abukva ,

My idea was that if I use RBMSymm with translational symmetry that would greatly simplify the problem

Depends what you mean by Simplifying the problem. You still are trying to solve a quantum mechanic hamiltonian with exponentially many degrees of freedom 2^N, and you are removing a number of N degrees of freedom, so that's really little.

Mainly, you are constraining the NQS to be symmetric, and you know the ground state is symmetric, which can speed up convergence and/or yield better results.

and I could run larger systems

Not really. Computational and memory cost will be comparable. Mainly you get better results.

there isn't any noticeable difference in the run time or…

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