xjc to generate packages from the xsd file <jxb:package name="example.test"/>

[deepres]

It seems I cannot leave the generatePackage empty because my sources will land in the generated package.

According to the docs:
https://jaxb.java.net/2.2.4/docs/xjc.html

Here under Compiler restrictions they claim that if you won't set the -p attribute the next choice is to look the xsd file, but I guess it's not happening. Can you tell me how I can accomplish that task ?

Example file

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
           xmlns:jxb="http://java.sun.com/xml/ns/jaxb"
           jxb:version="2.0"
           xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc"
           jxb:extensionBindingPrefixes="xjc">
  <xs:annotation>
    <xs:appinfo>
      <jxb:globalBindings>
        <xjc:simple />
      </jxb:globalBindings>
      <jxb:schemaBindings>
        <jxb:package name="com.custom.package"/>
      </jxb:schemaBindings>
    </xs:appinfo>
  </xs:annotation>
</xs:schema>

[scubacabra]

I'm actually not real sure anymore. It has been so long since I worked with xsd's. I've also never used the jxb:globalBindings like you use here.

I know I never personally used generatePackage because I always specified the package in every xsd and it worked for me before.

You could try setting the generatePackage whatever you have in the jxb:package. That might work. If you are looking to set them in xmlns you can check out the really simple xsd's in the examples folder of this repo.