Alphabet symmetry.js

// Consider the word "abode". We can see that the letter a is in position 1 and b is in position 2. In the alphabet, a and b are also in positions 1 and 2. Notice also that d and e in abode occupy the positions they would occupy in the alphabet, which are positions 4 and 5.

// Given an array of words, return an array of the number of letters that occupy their positions in the alphabet for each word. For example,

// solve(["abode","ABc","xyzD"]) = [4, 3, 1]

//P:
//R:
//E:
//P:
function solve(arr){  
    var alphabeth = "abcdefghijklmnopqrstuvwxyz";
    return arr.map(x => x.toLowerCase().split('').filter((y,i) => i==alphabeth.indexOf(y)).length);
  };
  console.log(solve(["abode","ABc","xyzD"]),[4,3,1])
  console.log(solve(["abide","ABc","xyz"]),[4,3,0])
  console.log(solve(["IAMDEFANDJKL","thedefgh","xyzDEFghijabc"]),[6, 5, 7])
  console.log(solve(["encode","abc","xyzD","ABmD"]),[1, 3, 1, 3])