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One possible answer is shown below.
public class Eagle extends Critter { private int multiplier; private int colorCount; private boolean isRed; public Eagle() { multiplier = 1; colorCount = 0; isRed = true; } public Action getMove(CritterInfo info) { colorCount++; if (colorCount == multiplier) { colorCount = 0; if (!isRed) { multiplier++; } isRed = !isRed; } if (info.getFront() == Neighbor.EMPTY) { return Action.HOP; } else if (info.getFront() == Neighbor.WALL) { return Action.RIGHT; } else { return Action.INFECT; } } public Color getColor() { if (isRed) { return Color.RED; } else { return Color.BLUE; } } public String toString() { return "<>"; } }
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One possible answer is shown below.
public static void manyStrings(ArrayList<String> list, int n) { for (int i = 0; i < list.size(); i+=n) { String word = list.get(i); for (int j = 1; j < n; j++) { list.add(i + j, word); } } }
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One possible answer is shown below.
public static boolean allPlural(String[] list) { for (int i = 0; i < list.length; i++) { if (!list[i].toLowerCase().endsWith("s")) { return false; } } return true; }