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// maximum Circular SubArray sum problem | ||
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#include<iostream> | ||
#include<climits> | ||
using namespace std; | ||
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int kadane(int arr[], int n){ | ||
int currSum = 0; | ||
int maxSum = INT_MIN; | ||
for(int i=0; i<n; i++){ | ||
currSum += arr[i]; | ||
if(currSum<0) | ||
currSum = 0; | ||
maxSum = max(maxSum, currSum); | ||
} | ||
return maxSum; | ||
} | ||
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int main() | ||
{ | ||
int n; | ||
cin>>n; | ||
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int arr[n]; | ||
for(int i=0; i<n; i++){ | ||
cin>>arr[i]; | ||
} | ||
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int wrapsum= 0; | ||
int nonwrapsum = 0; | ||
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nonwrapsum = kadane(arr, n); | ||
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int totalSum = 0; | ||
for(int i=0; i<n; i++){ | ||
totalSum += arr[i]; | ||
arr[i] = -arr[i]; | ||
} | ||
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wrapsum = totalSum-(-kadane(arr, n)); | ||
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cout<<max(wrapsum, nonwrapsum)<<endl; | ||
return 0; | ||
} |
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// first repeating element | ||
// Amazon, Oracle | ||
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#include"bits/stdc++.h" | ||
using namespace std; | ||
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int main() | ||
{ | ||
int n; | ||
cin>>n; | ||
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int arr[n]; | ||
for(int i=0; i<n; i++) | ||
{ | ||
cin>>arr[i]; | ||
} | ||
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const int N = 1e6+2; | ||
int idx[N]; | ||
for(int i=0; i<n; i++) | ||
{ | ||
idx[i]=-1; | ||
} | ||
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int minidx = INT_MAX; | ||
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for(int i=0; i<n; i++) | ||
{ | ||
if(idx[arr[i]] != -1) | ||
{ | ||
minidx = min(minidx, idx[arr[i]]); | ||
} | ||
else | ||
{ | ||
idx[arr[i]] = i; | ||
} | ||
} | ||
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if(minidx == INT_MAX) | ||
cout<<"-1"<<endl; | ||
else | ||
cout<<minidx+1<<endl; | ||
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return 0; | ||
} |
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// maximum subArray sum problem | ||
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#include<iostream> | ||
#include<climits> | ||
using namespace std; | ||
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int main() | ||
{ | ||
int n; | ||
cin>>n; | ||
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int arr[n]; | ||
for(int i=0; i<n; i++){ | ||
cin>>arr[i]; | ||
} | ||
// Brute force Approach - O(n3) | ||
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/*int maxSum = INT_MIN; | ||
for(int i=0; i<n; i++){ | ||
for(int j=i; j<n; j++){ | ||
int sum = 0; | ||
for(int k=i; k<=j; k++){ | ||
sum += arr[k]; | ||
//cout<<arr[k]<<" "; | ||
} | ||
//cout<<endl; | ||
maxSum=max(maxSum, sum); | ||
} | ||
}*/ | ||
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// cumiletive Sum Approach- O(n2) | ||
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/*int currSum[n+1]; | ||
currSum[0] = 0; | ||
for(int i=1; i<=n; i++){ | ||
currSum[i] = currSum[i-1]+arr[i-1]; | ||
} | ||
int maxSum = INT_MIN; | ||
for(int i=1; i<=n; i++){ | ||
int sum=0; | ||
for(int j=0; j<i; j++){ | ||
sum = currSum[i]-currSum[j]; | ||
maxSum = max(sum, maxSum); | ||
} | ||
}*/ | ||
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// Kadane's Algorithm - O(n) | ||
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int currentSum = 0; | ||
int maxSum = INT_MIN; | ||
for(int i=0; i<n; i++){ | ||
currentSum += arr[i]; | ||
if (currentSum<0) | ||
currentSum = 0; | ||
maxSum = max(maxSum, currentSum); | ||
} | ||
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cout<<maxSum<<endl; | ||
return 0; | ||
} |
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// Pair Sum problem | ||
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#include<iostream> | ||
#include<climits> | ||
#include<algorithm> | ||
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using namespace std; | ||
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bool pairsum(int arr[], int n, int k){ | ||
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// time - O(n2) | ||
/*for(int i=0; i<n-1; i++){ | ||
for(int j=i+1; j<n; j++){ | ||
if(arr[i]+arr[j]==k){ | ||
cout<<i<<" "<<j<<endl; | ||
return true; | ||
} | ||
} | ||
} | ||
return false; | ||
*/ | ||
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// time -- O(n) | ||
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int low = 0; | ||
int high = n-1; | ||
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while(low<high){ | ||
if(arr[low]+arr[high]==k){ | ||
cout<<low<<" "<<high<<endl; | ||
return true; | ||
} | ||
else if(arr[low]+arr[high]>k){ | ||
high--; | ||
} | ||
else{ | ||
low++; | ||
} | ||
} | ||
return false; | ||
} | ||
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int main() | ||
{ | ||
int n; | ||
cin>>n; | ||
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int arr[n]; | ||
for(int i=0; i<n; i++){ | ||
cin>>arr[i]; | ||
} | ||
int k; | ||
cin>>k; | ||
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cout<<pairsum(arr, n, k)<<endl; | ||
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return 0; | ||
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} |
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// smallest positive missing number | ||
// Accolite, Amazon, Sumsung, Snapdeal | ||
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#include"bits/stdc++.h" | ||
using namespace std; | ||
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int main() | ||
{ | ||
int n; | ||
cin>>n; | ||
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int arr[n]; | ||
for(int i=0; i<n; i++) | ||
{ | ||
cin>>arr[i]; | ||
} | ||
const int N = 1e6+2; | ||
bool check[N]; | ||
for(int i=0; i<n; i++) | ||
{ | ||
check[i] = 0; | ||
} | ||
for(int i=0; i<n; i++) | ||
{ | ||
if(arr[i]>=0) | ||
{ | ||
check[arr[i]] = 1; | ||
} | ||
} | ||
int ans = -1; | ||
for(int i=1; i<N; i++) | ||
{ | ||
if(check[i]==false) | ||
{ | ||
ans = i; | ||
break; | ||
} | ||
} | ||
cout<< ans << endl; | ||
return 0; | ||
} |
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//subArray with given Sum | ||
// Google, Amazon, Facebook, VISA | ||
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#include"bits/stdc++.h" | ||
using namespace std; | ||
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int main() | ||
{ | ||
int n, s; | ||
cin>>n >>s; | ||
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int arr[n]; | ||
for(int i=0; i<n; i++) | ||
{ | ||
cin>>arr[i]; | ||
} | ||
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int i=0, j=0, st=-1, en=-1, sum=0; | ||
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while(j<n && sum+arr[j]<=s) | ||
{ | ||
sum +=arr[j]; | ||
j++; | ||
} | ||
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if(sum == s) | ||
{ | ||
cout<< i+1<<" "<<j <<endl; | ||
return 0; | ||
} | ||
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while(j<n) | ||
{ | ||
sum += arr[j]; | ||
while(sum>s) | ||
{ | ||
sum -= arr[i]; | ||
i++; | ||
} | ||
if(sum==s) | ||
{ | ||
st = i+1; | ||
en = j+1; | ||
break; | ||
} | ||
j++; | ||
} | ||
cout<<st <<" " <<en <<endl; | ||
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return 0; | ||
} |